|
|
Math
      Location: IAKSS | MathCounts Puzzle of the Week:
If x=.9 repeating, then 10x = 9.9 repeating.
So, 10x - x = 9.9 repeating -.9 repeating.
If that is true, then, 9x/9 = 9/9 so, x must = 1 and therefore .9 repeating actually equals 1.
We know that is not true and therefore the problem is incorrect.
So, where's the error? |
|
|
|

Math
Posts: 281
     Location: Henry Clay | .9 repeating does equal 1 |
|
|
|

Math
Posts: 281
     Location: Henry Clay | 1/3 = .3 repeating
1=3(1/3) = 3(.3 repeating) = .9 repeating |
|
|
|
Math
Posts: 79
   Location: Tates Creek | .9 repeating is actually one of the only few ambiguous cases in mathematics. Its in an error in the notation we have accepted for decimal expansions. Another proof that .9 repeating equals one is through geometric series. 9\10 + 9\100 + 9\1000 + ...
So a = 9\10 and r = 1\10, thus a/(1-r) = 1. |
|
|
|

Math
Posts: 281
     Location: Henry Clay | Thought this was funny:
(series.jpg)
Attachments ----------------
series.jpg (20KB - 436 downloads)
|
|
|